User priyapatel | Submitted | Dofollow Social Bookmarking Sites 2016
Facing issue in account approval? email us at info@ipt.pw

Click to Ckeck Our - FREE SEO TOOLS

Avatar
Priyapatel

0 Following 0 Followers
1
The frequency of spring oscillator isν = 12πkmν ∝ 1mv1v2 = m2m1m2m1 = v1v22= v2v2 = 14m2 = m14
1
We have x2 – 5x + 6 – x2 – 3x – 2x + 6= (x – 3) (x – 2)So, the value of x2 – 5x + 6 is zero when x - 3 = 0 or x – 2 = 0i.e., when x = 3 or x = 2Therefore, the zeroes of x2 – 5x + 6 are 3 and 2.Sum of zeroes =                         = Product of zeroes
1
Venturimeter is based on Bernoulli s theorem. It consists of a two truncated tubes connected by a pipe at narrow ends. The pipe connecting the two tubes is called throat as shown in figure.
The venturimeter tube is positioned horizontally and the liquid is made to enter in it at end A and after passing through throat BC, it leaves tube at end D. Let at A, the area of cross-section of tube be a1, pressure of liquid be P1 and velocity be v1 And at the throat, the area of cross-section of tube be a2 pressure of liquid be P2 and velocity be v2
1
Vander Waal s radius is defined as one half of the distance between the nuclei of two adjacent atoms belonging to two neighbouringmolecules of an element in the solid state, vander Waal’s radii are determined by X-ray diffraction method.Comparison of covalent radius and vander Waal’s radius.vander Waal’s radii are always larger than covalent radii. This is because for the formation of covalent bond, atoms move to come closer to each other due to the overlapping of orbitals. On the other hand, vander Waal’s forces operating between atoms are weak, therefore, adjacent atoms belonging to two nei
1
Metal oxide = M0.98O If ‘x’ ions of M are in +3 state, then 3x + (0.98 – x) × 2 = 2 x = 0.04 So the percentage of metal in +3 state would be
1
(i) Join 1 Ω, 2 Ω in parallel and the combination in series with 3 Ω. (ii) parallel combination of 2 Ω and 3 Ω in series with 1 Ω. (iii) all in series (iv) all in parallel.
1
Given ,  u = - mf∴  1v - 1(-mf) = - 1f⇒                    1v = - 1f 1 + 1m⇒                - vf = mm + 1⇒                - vu = 11 + m